Technetium si è venuto il tecnico che sostiene che il valore è normale. Noi abbiamo lo switch anche con porte a 2,5 e 10Gb..... Può migliorare qualcosa?
Come si fa il test da terminale?
mariop siamo a circa 750€ mese
QUesta è il parere di ChatGPT:
Domanda: what is the tcp ip overhead on a 1gb link?
Risposta: Calculating the TCP/IP overhead on a 1 Gb (gigabit) link involves understanding the structure of TCP/IP packets and the bandwidth they consume. Here's a breakdown of the overhead:
- TCP Overhead: A typical TCP header is 20 bytes. There could be additional options that increase this size, but the standard header is usually considered for basic calculations.
- IP Overhead: An IPv4 header is also 20 bytes, and an IPv6 header is 40 bytes. For this example, let's consider IPv4.
- Ethernet Overhead: The Ethernet frame, which encapsulates the IP packet, adds its own overhead. This includes:
- Preamble and Start of Frame Delimiter (SFD): 8 bytes
- Ethernet Header (Source and Destination MAC, EtherType): 14 bytes
- Frame Check Sequence (FCS): 4 bytes
- Interpacket Gap (IPG): Typically 12 bytes. It's a gap between packets to prevent collisions and is considered part of the overhead in terms of effective bandwidth usage.
So, for a single Ethernet frame carrying a TCP/IP packet, the overhead is:
- TCP: 20 bytes
- IP: 20 bytes
- Ethernet: 36 bytes (8 bytes for Preamble + SFD, 14 bytes for Header, 4 bytes for FCS, and about 12 bytes for IPG)
This sums up to 76 bytes of overhead per packet.
To determine the overhead on a 1 Gb link, you also need to know the size of the data being transferred in each packet. Ethernet has a maximum frame size of 1500 bytes (MTU), of which the data payload is typically less due to the overhead.
Let's calculate the overhead percentage in a typical maximum-sized Ethernet frame:
- Total frame size: 1500 bytes (MTU)
- Overhead per frame: 76 bytes
- Payload per frame: 1500 - 76 = 1424 bytes
The overhead percentage can be calculated as (Overhead / Total Frame Size) * 100.
Let's do the math to find out the exact percentage.
The overhead percentage for TCP/IP on an Ethernet frame with a maximum transmission unit (MTU) of 1500 bytes is approximately 5.07%. This means that on a 1 Gb (gigabit per second) link, about 5.07% of the bandwidth could be consumed by TCP/IP and Ethernet overhead under maximum utilization with standard-sized frames.
Domanda: in terms of bandwidth, what would be the maximum speed?
Risposta: To calculate the effective maximum data transfer speed on a 1 Gb/s link, considering the TCP/IP and Ethernet overhead, we can use the overhead percentage we calculated earlier.
We found that the overhead is approximately 5.07%. This means that 5.07% of the bandwidth is used for overhead, and the remaining 94.93% is available for actual data transmission.
The theoretical maximum speed of the link is 1 Gb/s (gigabits per second), which is equivalent to 1000 Mb/s (megabits per second). To find the effective maximum speed:
- Effective Data Rate = Total Link Speed × (1 - Overhead Percentage)
Let's calculate the effective data rate for a 1 Gb/s link.
The effective maximum data transfer speed on a 1 Gb/s link, after accounting for approximately 5.07% TCP/IP and Ethernet overhead, is around 949.33 Mb/s (megabits per second). This is the bandwidth available for actual data transmission under ideal conditions.
🤣
